890=-16x^2+1500

Solution for 890=-16x^2+1500 equation:

890=-16x^2+1500

We move all terms to the left:

890-(-16x^2+1500)=0

We get rid of parentheses

16x^2-1500+890=0

We add all the numbers together, and all the variables

16x^2-610=0

a = 16; b = 0; c = -610;
Δ = b2-4ac
Δ = 02-4·16·(-610)
Δ = 39040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{39040}=\sqrt{64*610}=\sqrt{64}*\sqrt{610}=8\sqrt{610}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{610}}{2*16}=\frac{0-8\sqrt{610}}{32}
=-\frac{8\sqrt{610}}{32}
=-\frac{\sqrt{610}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{610}}{2*16}=\frac{0+8\sqrt{610}}{32}
=\frac{8\sqrt{610}}{32}
=\frac{\sqrt{610}}{4}
$